How could you write a quadratic function in factored form that would have a vertex with an x coordinate of 3 and two distinct roots

The vertex lies on the axis of symmetry so the axis of symmetry is x = 3. Find any two intercepts that are equal distance from the axis of symmetry. Use those intercepts to write factors of the function by subtracting their values from x. For example, 2 and 4 are each 1 unit from x = 3 so f(x) = (x – 2)(x – 4) is a possible function. Trust me this is the answer

location: point 0

step-by-step explanation:

well, -8 to 10 on a number line is 18 spaces.

1/9 of 18 is 2.

so, 4/9 of 18 must be 8.

8 spaces from -8 (a) is 0.

so, 4/9 of the way from -8 to 10 is 0!