What are the zeros for the function b(t) = (t – 5) (t + 3) (t – 2)?

t=5           t=-3          t=2

Step-by-step explanation:

b(t) = (t – 5) (t + 3) (t – 2)

Set the function equal to zero

0  = (t – 5) (t + 3) (t – 2)

We can use the zero product property

t-5 =0     t+3 =0       t-2=0

t=5           t=-3          t=2

ghjmutmum

step-by-step explanation:

a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58