A bag contains 120 identical balls (e. g., in size, shape, and weight) except their color. Of the 120, 90 balls are red and 30 balls are green. We can not see inside the bag. Two balls are chosen at random without replacement. Calculate the following probabilities.

(a) What is the probability that the first ball chosen is red?
(b) What is the probability that both balls are red?
(c) What is the probability that at least one ball is red?
(d) What is the probability that the second ball chosen is green?
(e) What is the probability that the first ball chosen is red given that the second ball is green?

answer: b.

step-by-step explanation:

the y coordinate for point b is 0, and answer b is the only one with that y coordinate.

c 1 hour

step-by-step explanation:

m = 2e

m = 2 so 2 = 2e

1 = e

step-by-step explanation:

the answer is 128

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west