What is the effect in the time required to solve a problem when you double the size of the input from n to 2n, assuming that the number of milliseconds the algorithm uses to solve the problem with input size n is:a) log log nb) log nc) 100nd) n log ne) n^2f) n^3g) 2^n

answer: sine

step-by-step explanation:

i need points

step-by-step explanation:

sorry bubs

step-by-step explanation:

let pq = qr = rs = x, and xz = y and zu = z.

if the horizontal lines are parallel, then corresponding segments are in proportion:

substitute:

therefore 3 = y = z.

xu = y + z → xu = 3 + 3 = 6

time is equal to distance over rate so

t = d/r

need a little bit more information for the second question.