What value of n makes the equation true? (2x^9 y^n) (4x^2 y^10) =8x^11 y^20

n =10

Step-by-step explanation:

(2x⁹ yⁿ)(4x² y¹⁰)= 8x¹¹ y²⁰

2*4*x⁹*x²* yⁿ* y¹⁰= 8x¹¹ y²⁰

8x⁹⁺² * yⁿ⁺¹⁰ = 8x¹¹y²⁰

8x¹¹yⁿ⁺¹⁰ = 8x¹¹y²⁰

Now, compare the powers of y

n +10 = 20

n = 20 -10

n =10

step-by-step explanation:

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