A company advertises two car tire models. The number of thousands of miles that the standard model tires last has a mean \mu_S = 60μ S =60 and standard deviation \sigma_S = 5σ S =5. The number of miles that the extended life tires last has a mean \mu_E = 70μ E =70 and standard deviation \sigma_E = 7σ E =7. If mileages for both tires follow a normal distribution, what is the probability that a randomly selected standard model tire will get more mileage than a randomly selected extended life tire?

0.123

Step-by-step explanation:

Use the random variable E - S, which will follow a normal distribution with a mean of 70 - 60 = 10 and SD = \sqrt{5^2+7^}

P(E - S < 0) = 0.123

step-by-step explanation:

consider the parallelogram shown in the attached image.

in the parallelogram hijk, the length of hk is given as,

from the properties of parallelogram we know that the opposite sides of a parallelogram are parallel to each other and are equal in measure.

therefore, the length of the side ij must be equal to the length of the side hk and that is .

hence, the expression for the length of ij confirms that hijk is a parallelogram.