Six people, named Anna, Bob, Chandra, Darlene, Ed, and Frank, will be interviewed for a job. The interviewer will choose two at random to interview on the first day. What is the probability that Darlene is interviewed first and Bob is interviewed second? Express your answer as a fraction or a decimal, rounded to four decimal places.

Your answer is 1/30, or 0.0333

The interviewer has a 1/6 chance of choosing Darlene first because all of the people have an equal chance and there are 6 people.
The interviewer then has a 1/5 chance of choosing Bob second, because Darlene has already been chosen so there are now only 5 people to choose from.

Therefore we do 1/6 × 1/5 = 1/30 = 0.0333

I hope this helps!

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