. Consider the matrix, right side vector, and two approximate solutions, A = 0.913 0.659 0.457 0.330 , b = 0.254 0.127 , x1 = −0.0827 0.5 , x2 = 0.999 −1.001 . The true solution is x = [1, −1]T . (a) Compute the norm of error and residual vectors for both x1 and x2 using the [infinity]-norm. (b) x = [1, −1]T is the true solution, so clearly x2 is the more accurate approximation. If you did not know this, given the results of (a), would you have a strong reason to pick one approximate solution over the other by just looking at the norm of the residual?

the largest number of the four options is 1.8 x 10-2

you have it in scientific notation.

1.80 x 10-6   = 0.00000180

1.80 x 10-4   = 0.000180 (bigger, or "less small", than the former one)

so

1.8 x 10-2       = 0.0180. as you see. the "less small", or the biggest one of them all.

as you have negative exponent, it means you are dividing 1.8 by 100 (i.e. moving the dot towards left, two times).

if you had positive exponent for the scientific notation, power of tenths, you would be multiplying times 100 (moving the dot towards right) as below:

1.8 x (10)2 = 180

so. if you have negative exponent in scientific notation, move the dot toward left. if it is positive, toward right as many times the exponent tells you.

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step-by-step explanation:

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step-by-step explanation: