2.

John is going to reach into a jar and randomly pick two pieces of candy from the three different types of candy bars that are in the candy jar. The three candy bars are Snickers, Milky Way, and a Three Musketeers. What is the probability he will select a Milky Way first and a Snickers second if we use replacement (puts the first selected bar back in the jar)?

1/3

1/6

1/9

1/27

1/9 is probably most likely the correct answer

yes the total will be same because in both of them the expression.is rearranged but their sign remains the same hence it hss just been shuffled

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0