What is the value of x in the equation 6(x + 1) – 5x = 8 + 2(x - 1)?
OIT MT

x=0

Step-by-step explanation:

To solve, we need to get all the variables on one side of the equation, and all the numbers on the other

6(x + 1) – 5x = 8 + 2(x - 1)

First, distribute the 6 on the left

6*x+6*1 -5x=8 +2(x-1)

6x+6-5x=8+2(x=1)

Combine like terms on the left

(6x-5x)+6=8+2(x-1)

x+6=8+2(x-1)

Distribute the 2 on the right

x+6=8+2*x+2*-1

x+6=8+2x-2

Combine like terms on the right

x+6=2x+(8-2)

x+6=2x+6

Subtract x from both sides

6=x+6

Subtract 6 from both sides

x=0

Hope this helps! :)

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