The difference of the two solutions of x^2+19x+c=0 is 15. Find c.

The value of is 34.

It is given that,

Explanation:

Let and are two solutions of the given equation.

          ...(i)

The sum of solutions of is . So,

         ...(ii)

Adding (i) and (ii), we get

Substitute in (ii).

The product of solutions of is . So,

Thus, the value of is 34.

Learn more:

link

34

Step-by-step explanation:

For a quadratic equation ax² + bx + c = 0, the sum of the roots is -b/a, and the product of the roots is c/a.

If we say the roots are p and q, then:

p + q = -19/1

pq = c/1

The difference of the roots is 15:

p − q = 15

Add to the first equation:

2p = -4

p = -2

Which means the value of q is -17.

So the value of c is (-2)(-17) = 34.

you can not drow on this

step-by-step explanation: