You send a beam of light from a material with index of refraction 1.25 1.25 into an unknown material. In order to help identify this material, you determine its index of refraction by measuring the angles of incidence and refraction for which you find the values 40.1 ∘ 40.1∘ and 36.9 ∘ , 36.9∘, respectively. What is the index of refraction n n of the unknown material?

  1.34

Step-by-step explanation:

Snell's law tells you ...

Solving for , we get ...

The unknown material has an index of refraction of 1.34.

answer:  

step-by-step explanation:

here x represents the height of the pole,

and, the height of the shadow of the pole is 12 feet.

also, the angle of elevation from the top of the pole is 40°,

therefore,

by the low of sine,

which is the required equation for finding the value of x,

because linear equations are a lot simpler than quadratics equations, and linear equations formula is a lot easier to memorize. that's why i think they're harder.