In this problem you will calculate ∫305x3dx by using the formal definition of the definite integral: ∫baf(x)dx=limn→[infinity][∑k=1nf(x∗ k)Δx]. (a) The interval [0,3] is divided into n equal subintervals of length Δx. What is Δx (in terms of n)? Δx = (b) The right-hand endpoint of the kth subinterval is denoted x∗k. What is x∗k (in terms of k and n)? x∗k = (c) Using these choices for x∗k and Δx, the definition tells us that ∫305x3dx=limn→[infinity][∑k=1nf(x∗k )Δx]. What is f(x∗k)Δx (in terms of k and n)? f(x∗k)Δx = (d) Express ∑k=1nf(x∗k)Δx in closed form. (Your answer will be in terms of n.) ∑k=1nf(x∗k)Δx = (e) Finally, complete the problem by taking the limit as n→[infinity] of the expression that you found in the previous part. ∫305x3dx=limn→[infinity][∑k=1nf(x∗k )Δx] =

answer: since the question is talking about growth you have to use the growth formula which is inital amount (1 + growth)^time

step-by-step explanation:

the intial amount is 1200, the growth is 4.8, and the time is 7. plug those numbers into the equation, also i think you have to change 4.8 into a percent. but, i have forgotton how to do that. if this is a online class go on to the lesson.

3x + 4y -25 =0 represents the amount of change sianna should recieve

aloha~! my name is zalgo and i am here to you out on this amazing day. to answer your question, yes, nonzero numbers can have a greatest common factor and that would be 1. still don't get it? let me considering every number is divisible by 1 and hence every number has 1 as a factor of theirs. so, if 2 nonzero numbers didn't share any gcf (greatest common factor), they would still have a factor in common and that would be 1.

i hope that this ! : p

"stay and stay proud! " - zalgo

(by the way, do you mind marking me as brainliest? i'd greatly appreciate it! mahalo! x3)