A scientist needs 120 ML of a 20% acid solution for an experiment. The lab has available at 10% solution and a 25% solution. How many milliliters of the 10% solution and how many milliliters of a 25% solution should the scientist mix to make the 20% solution?

40 milliliters of the 10% solution and 80 milliliters of the 25% solution the scientist should mix to make the 20% solution.

Step-by-step explanation:

Given:

A scientist needs 120 ML of a 20% acid solution for an experiment. The lab has available at 10% solution and a 25% solution.

Now, to find the milliliters of 10% solution and 25% solution to make 20% solution:

Let the 10% solution be

And let the 25% solution be

So, total milliliters of solution are:

Now, to get the milliliters of 10% solution and 25% solution to make 20% solution we solve the equation:

Substituting the value of from equation (1) we get:

Subtracting both sides by 12 we get:

Dividing both sides by 0.15 we get:

Thus, the 25% solution is 80 ml.

Now, substituting the value of in equation (1) we get:

Hence, the 10% solution is 40 ml.

Therefore, 40 milliliters of the 10% solution and 80 milliliters of the 25% solution the scientist should mix to make the 20% solution.

welll its a very hard question but ill

step-by-step explanation:

first you take the 6 dollars and add 10 to it then add the 50 to that then multiply by 8 with xy and your answer will be

hope this

yes

step-by-step explanation:

yes