A research scholar wants to know how many times per hour a certain strand of virus reproduces. The mean is found to be 13.7 reproductions and the population standard deviation is known to be 2. If a sample of 205 was used for the study, construct the 80% confidence interval for the true mean number of reproductions per hour for the virus. Round your answers to one decimal place.

The 80% confidence interval for the true mean number of reproductions per hour for the virus.

(13.52 , 13.87)

Step-by-step explanation:

Explanation:-

The mean is found to be 13.7 reproductions and the population standard deviation is known to be 2

the mean of the sample x⁻ = 13.7

The standard deviation of population σ = 2

Given sample size n =205

The 80% of confidence intervals:-

(13.52 , 13.87)

Conclusion:-

the 80% confidence interval for the true mean number of reproductions per hour for the virus.

(13.52 , 13.87)

idk

step-by-step explanation:

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.