The area of a circular base of the larger cylinder is 81π. The area of a circular base of the smaller cylinder is 9π.

Make a conjecture about the similar solids. How is the scale factor and the ratio of the surface areas related? Check all that apply.

- The dimensions of the larger cylinder are 3 times the dimensions of the smaller cylinder.
- The surface area of the larger cylinder is 32, or 9, times the surface area of the smaller cylinder.
- If proportional dimensional changes are made to a solid figure, then the surface area will change by the square of the scale factor of similar solids.

A & C

The dimensions of the larger cylinder are 3 times the dimensions of the smaller cylinder.

If proportional dimensional changes are made to a solid figure, then the surface area will change by the square of the scale factor of similar solids.

Step-by-step explanation:

ian gone lie this got me confused

step-by-step explanation:

place r′ so that qr′ is parallel to the tangent.

now we get that ∠r′py=∠pr′q, where y is on the tangent, on the opposite side of p from x.

also, because of the symmetry, ∠r′py=∠qpx.

finally, note that no matter where we place r, as long as it's on the correct arc, we have ∠prq=∠pr′q.

stringing all these equalities together, we end up with ∠prq=∠qpx.

this picture will show how its going to look like.

hope this by jack monhen