In triangle ABC , angle C is a right angle. If cos A = 5/8 what is the value of cos B?

Sqrt(39)/8

Step-by-step explanation:

cos = adjacent/hypotenuse

cos A = 5/8

this means adjacent of angle a is 5 and hypotenuse is 8

for cos B, adjacent will be variable x and hypotenuse is 8

now to find x, use a^2 + b^2 = c^2, which then we will use to find cos B

x^2 + 5^2 = 8^2

x^2 + 25 = 64

x^2 = 64-25 = 39

x = sqrt(39)

thus cos B = sqrt(39)/8

the answer is 48m^2!

step-by-step explanation: