Mathematics, 15.04.2020 21:08 LuvieAnn1886
Divya and Miguel were asked to find an explicit formula for the sequence 80\,,\,40\,,\,20\,,\,10,...80,40,20 ,10,...80, comma, 40, comma, 20, comma, 10, comma, point, point, point. Divya said the formula is h(n)=80\cdot\left(\dfrac{1}{2}\righ t)^{\large{n-1}}h(n)=80β ( 2 1 ) nβ1 h, left parenthesis, n, right parenthesis, equals, 80, dot, left parenthesis, start fraction, 1, divided by, 2, end fraction, right parenthesis, start superscript, n, minus, 1, end superscript, and Miguel said the formula is h(n)=160\cdot\left(\dfrac{1}{2}\rig ht)^{\large{n}}h(n)=160β ( 2 1 ) n h, left parenthesis, n, right parenthesis, equals, 160, dot, left parenthesis, start fraction, 1, divided by, 2, end fraction, right parenthesis, start superscript, n, end superscript.
Answers: 3
Mathematics, 21.06.2019 15:00
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Answers: 3
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Divya and Miguel were asked to find an explicit formula for the sequence 80\,,\,40\,,\,20\,,\,10,......
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