Use the drop downs to answer the following questions of finding the distance from (–6, 2) to the origin. Use (0, 0) as (x1, y1).

d = StartRoot (x 2 minus x 1) squared + (y 2 minus y 1) squared EndRoot

What is the difference of the x-coordinates, (x2–x1)?

What is the difference of the y-coordinates, (y2–y1)?

What is the distance from (–6, 2) to the origin?

step-by-step explanation:

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(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

6 meters

step-by-step explanation: