The size of a computer monitor is the length of its diagonal. You want to buy a 19-in. monitor that has a height of 11 in. What is the width of the monitor? Round to the nearest tenth of an inch.

15.5 inches

Step-by-step explanation:

Using the Pythagorean theorem; The square of the hypotenuse is equal to the sum of the squares of the two adjacent sides

The diagonal is the longest side of a rectangle so it becomes the hypotenuse

Let w represent the width

19^2 = 11^2 + w^2

19^2 - 11^2 = w^2

361 - 121 =  w^2

240 = w^2

w =

w = 15.5 inches

it is contrapositive

i could not see the question too well so check yourself again too . this is because i want you to get it correct.

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.