) Four congruent square pieces with lengths of sides of 6 cm were cut out of corners of a square piece of cardboard. Then this piece of cardboard was folded into an open-top box. Find the original dimensions of the piece of cardboard if the volume of the resulting box is 486 cm3.

21x21 cm

Step-by-step explanation:

Volume =whl

Given: V=486, and h=6, and w=l

So we can it into this equation: 486=6(l^2)

to solve we isolate the variable by dividing each side by factors that don't contain the variable.

which therefore l = 9

Then we add 6(height) +9(l)+6(width)

6+9+6=21 therefore the sides of cardboard are 21 cm × 21 cm

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation:

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