Ryan will rent a car for the weekend. He can choose one of two plans. The first plan has an initial fee of and costs an additional per mile driven. The second plan has an initial fee of and costs an additional per mile driven. How many miles would Ryan need to drive for the two plans to cost the same?

Question:

Ryan will rent a car for the weekend. He can choose one of two plans. The first plan has an initial fee of $57.98 and costs an additional $0.14 per mile driven. The second plan has an initial fee of 53.98 and costs an additional $0.16 per mile driven. How many miles would Ryan need to drive for the two plans to cost the same?

The number of miles Ryan needs to drive for the two plans to cost the same is 200 miles

Step-by-step explanation:

Here we have

The initial fee of the first plan =  $57.98

Additional mile cost of the first plan = $0.14

The initial fee of the second plan =  $53.98

Additional mile cost of the first plan = $0.16

Let the mileage required for the two plans to cost the same be Y miles

Therefore,

$57.98 + $0.14 ×Y = $53.98 + $0.16 ×Y

$0.16 ×Y - $0.14 ×Y = $57.98 - $53.98 = $4.00

$0.02 ×Y = $4.00

Y = 200 miles

The number of miles driven for the two plans to cost the same = 200 miles.

a=r

d=q

c=p

b=s

hope this !

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