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Mathematics, 15.04.2020 02:58 carter1809

H(1)=βˆ’2
h(2)=1
h(n)=h(nβˆ’2)+h(nβˆ’1)
what is h(3)???

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Answers: 1

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You know the right answer?
H(1)=βˆ’2
h(2)=1
h(n)=h(nβˆ’2)+h(nβˆ’1)
what is h(3)???...
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