Circle Y is shown. Line segments X Y and Z Y are radii. The length of X Y is 16. Sector X Y Z of the minor angle is shaded.
The measure of central angle XYZ is StartFraction 3 pi Over 4 EndFraction radians.

What is the area of the shaded sector?

32Pi units squared
85
96Pi units squared
256Pi units squared

½ × 16² × (3pi/4)

96pi units²

Step-by-step explanation:

We can solve for the area of the sector using the formula [ A = 1/2 * r² * θ]. Note that θ equals the measure for the central angle which 3π/4

A = 1/2 * 16² * 3π/4

A = 1/2 * 256 * 3π/4

A = 128 * 3π/4

A = 3π128/4

A = 384π/4

A = 96π

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2