Given three non-collinear points $A$, $B$, and $C$, construct three circles that are pairwise tangent at these points. (In other words, two of the three circles are tangent at $A$, two are tangent at $B$, and two are tangent at $C$.) Are there any cases where such circles do not exist

$450.00 for 6 weeks

or

$300

step-by-step explanation:

$200.00 for first week $50.00 x5 equals $250 plus $200 equals $450.00 for six weeks.

$200 for first week

$200 x 0.10 = $20

$20 x 5 = $100

$200 + $100 = $300

the solution is the point

step-by-step explanation:

we have

> equation a

> equation b

adds equation a and equation b

substitute the value of x in equation b to find the value of y

the solution is the point

or