The distribution of certain test scores is a nonstandard normal distribution with a mean of 50 and a standard deviation of 6. What are the values of the mean and standard deviation after all test scores have been standardized by converting them to z-scores using zequalsStartFraction x minus mu Over sigma EndFraction
?

Mean value is 0 and standard deviation is 1 after all test scores have been standardized by converting them to z-scores using z

Step-by-step explanation:

In a standard normal distribution (also called as Gaussian distribution) all values of the sample can be projected to a normal distribution with mean 0 and standard deviation 1 using their z-scores.

z-score of a value X can be calculated as follows:

z= where

50 is the mean of the test scores

6 is the standard deviation of test scores

0 and 1

Step-by-step explanation:

Given that,

The distribution of certain test score is non- standard normal distribution with mean 50 and  a standard deviation of 6.

we know that the

standard normal deviation has mean 0 and standard deviation 1.

So, All test scores have been standardized by converting them to z score.

mean = 0 and standard deviation= 1

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c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

slope is 35 and 20 miles is the y-intercept.

step-by-step explanation: