×=-2 x intercept for the polynomial f(×)=×^3×^2-8×-12

x-intercepts are ...

Step-by-step explanation:

Indeed, x = -2 is an x-intercept of the polynomial ...

  f(x) = x^3 +x^2 -8x -12

The other x-intercepts are -2 and +3, meaning that x = -2 is a zero with multiplicity 2.

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I like a graph for sorting this out. If you want to determine the other roots algebraically, you can factor (x +2) from f(x) to find the remaining quadratic factor to be (x^2 -x -6). Then the complete factorization of f(x) is ...

  f(x) = (x +2)(x^2 -x -6) = (x +2)(x +2)(x -3)

  f(x) = (x +2)^2(x -3)

The given x-intercept has multiplicity 2. The remaining x-intercept is x = 3.

step-by-step explanation:

∆abc has the points a(1, 7), b(-2, 2), and c(4, 2) as its vertices. formed with the point d(1, 2) as its third vertex, then ∆abd is triangle.