Find the equation of the axis of symmetry of the following parabola algebraically.

y=3x²-48x+177

the equation of the axis of symmetry is

Step-by-step explanation:

Recall that the equation of the axis of symmetry for a parabola with vertical branches like this one, is an equation of a vertical line that passes through the very vertex of the parabola and divides it into its two symmetric branches. Such vertical line would have therefore an expression of the form: , being that constant the very x-coordinate of the vertex.

So we use for that the fact that the x position of  the vertex of a parabola of the general form: , is given by:

which in our case becomes:

Then, the equation of the axis of symmetry for this parabola is:

don't give

take it once

try and try and you will not

happy to

pls mark as brainliest

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.