The stem-and-leaf plot below shows the amount of tips received by the servers in a restaurant in one night.
A stem and leaf plot is shown. The stems from top to bottom are 0, 1, 2, 3, 5. The first column of leaves is 9, 2, 3, 1, 9. The second column of leaves is blank, 4, 6, 2, blank. The third column of leaves is blank 7, 6, 2, blank. The fourth column of leaves is blank, blank, 8, 4, blank. The fifth column of leaves is blank, blank, blank, 5, blank.
Why is the plot misleading?
The plot shows that the data is skewed.
There is not an equal number of data points for each stem.
The plot shows duplicate data points.
The stem does not clearly show the outlier.
ANSWER IS D

Stem and leaf plots are used to represent data by categorizing the dataset into stems and leaves.

The plot is misleading is (d) the stem does not clearly show the outlier.

From the given stem and leaf plots, the stems are 0, 1, 2, 3 and 5.

The stem omits number 4.

This implies that, 59 is an outlier of the dataset, because 59 is relatively far from the data elements

Because 4 is omitted from the stems, then the outlier would not be seen clearly

Hence, the plot is misleading because of (d)

Read more about stem and leaf plots at:

link

D. The stem does not clearly show the outlier.

Step-by-step explanation:

The stem used on the plot is 0, 1, 3, 5. There is one missing number in the stem, which is four. The two highest value in the plot is 59 and 35. The 59 value should be an outlier since it is 14 value higher than 35, the second-highest data value. But the plot makes it they look close since it doesn't write 4.

An outlier can easily skew the data and make the sample not giving a result that represents real-life data.

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17

table 3 represents a direct variation function. : )