Laboratory experiment shows that the life of the average butterfly is normally distributed with a mean of 18.8 days and a standard deviation of 2 days. Find the probability that a butterfly will live between 12.04 and 18.38 days.

41.64% probability that a butterfly will live between 12.04 and 18.38 days.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Find the probability that a butterfly will live between 12.04 and 18.38 days.

This is the pvalue of Z when X = 18.38 subtracted by the pvalue of Z when X = 12.04. So

X = 18.38

has a pvalue of 0.4168

X = 12.04

has a pvalue of 0.0004

0.4168 - 0.0004 = 0.4164

41.64% probability that a butterfly will live between 12.04 and 18.38 days.

ruth is 6 years old

step-by-step explanation:

6 + 24 = 30,   so 6/30 = .2  

if you do 1/5 it also equals .2, so that is the answer.

what level of math? also i don't need to be paid if i can you.