Suppose 1% of people in a large population are over 6 feet 3 inches tall. Approximately what is the chance that from a group of 200 people picked at random from this population, at least four people will be over 6 feet 3 inches tall

14.19% probability that from a group of 200 people picked at random from this population, at least four people will be over 6 feet 3 inches tall

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they are over 6 feet 3 inches tall, or they are not. The probability of a person being over this height is independent of any other person. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.

1% of people in a large population are over 6 feet 3 inches tall.

This means that

200 people

This means that

At least four people will be over 6 feet 3 inches tall

Either there is less than four people over this height, or there is more than 4 people. The sum of the probabilities of these events is decimal 1. So

We want . So

In which

14.19% probability that from a group of 200 people picked at random from this population, at least four people will be over 6 feet 3 inches tall

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing im pretty sure that is the right answer

step-by-step explanation:

360/29

step-by-step explanation: