A researcher compares the effectiveness of two different instructional methods for teaching anatomy. A sample of 293 students using Method 1 produces a testing average of 82.9. A sample of 282 students using Method 2 produces a testing average of 76.5. Assume that the population standard deviation for Method 1 is 7.97, while the population standard deviation for Method 2 is 6.66. Determine the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2. Step 1 of 3 : Find the point estimate for the true difference between the population means.

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (5.20, 7.60).

Step-by-step explanation:

The (1 - α)% confidence interval for the difference between two population mean when the population standard deviations are known is:

The information provided is:

The critical value of z for 98% confidence interval is:

*Use a z-table for the critical value.

Compute the 98% confidence interval for the difference between two population means as follows:

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (5.20, 7.60).

a rotation about point l

step-by-step explanation:

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