Can someone please find the area of this shape and show the work??
A) 6m^2
B) 18m^2
C) 21.5 m^2
D) 24.3 m^2
E) 30.3 m^2

E) 30.3 m^2

Step-by-step explanation:

First, find the area of the trapezoid, which is (a+b )h/2, or base 1 plus base 2 times height divided by 2. Solving, this gives you (2+10)4/2, or 24 m^2.

Next, find the area of the semicircle which is 1/2*pi*r^2, where r=d/2. Plugging this in, 1/2*pi*(4/2)^2 gives you about 6.3 m^2.

Adding, 24+6.3=30.3 m^2.

a function could be identified in 3 ways either on a chart,graph, or ordered pairs. first a function is that each point has its own. the rule is that there can be many x's to one y but there can not be 2 x's at different y's. so on a graph when you put a straight line through the y's there should be one dot only to be a function.

step-by-step explanation:

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)