PLEASE HELP 100 POINTS
Find the values of x and y in parallelogram PQRS.
PT=y, TR=2x+1, QT=4y, TS=6x+10
x= ? and y= ?

x=3   y=7

Step-by-step explanation:

PT=y, TR=2x+1, QT=4y, TS=6x+10

The diagonals of a parallelogram bisect each other

PT = TR    and  QT = TS

y = 2x+1     and 4y = 6x+10

We have a system of equations

Multiply the first equation by 4

4y = 8x+4   and 4y = 6x+10

Set them equal

8x+4 = 6x+10

Subtract 6x from each side

8x-6x+4 = 6x-6x +10

2x +4 = 10

Subtract 4

2x+4-4=10-4

2x =6

Divide each side by 2

2x=6/2

x=3

Now solve for y

y = 2x+1

  =2(3)+1

  =7

x = 3, y = 7

Step-by-step explanation:

Diagonals of a parallelogram bisect each other so both halves of each diagonal are equal

PT = TR

QT = TS

y = 2x + 1

4y = 6x + 10

4(2x + 1) = 6x + 10

8x + 4 = 6x + 10

2x = 6

x = 3

y = 2(3) + 1 = 7

srry idk

step-by-step explanation:

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17