Suizi bought 5 packages of M&M and each package contained 18 candy pieces. She opened the frist package and counted 4 green pieces. She then counted 3 green in the second package

Step-by-step explanation:

Here, the given question is incomplete.

Suzi bought 5 packages of M&M's, and each package contained 18 candy pieces. She opened the first package and counted 4 green pieces. She then counted 3 green pieces in the second package. Which statement about the candy pieces in the remaining packages is best supported by this information?

A. There are fewer than 14 green pieces in all 5 packages.

B. There are between 15 and 20 green pieces in all 5 packages.

C. There are at least 25 green pieces but no more than 50 in all 5 packages. D. There are more than 50 green pieces in all 5 packages.

Now, here given:

The number of packages of M & M purchased  = 5 packets

The number of candies in each packet = 18

The number of green candies in first pack  = 4

The number of green candies in second pack  = 3

Now as we can see the number of green candies in decreasing by 1 in number as we open more packets.

So, according to this pattern:

The number of green candies in third pack  = 2

The number of green candies in fourth pack  = 1

And the fifth pack will have NO green candies.

So, the total number of green candies in all 5 packets combined  

=  4  + 3+ 2 + 1 + 0

=  10 green candies

⇒  There are fewer than 14 green pieces in all 5 packages.

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.