How many real solutions does this system of equations have? X^2+ 3 = y
3x-y+1 = 0
Answer choices:
A.2
B.1
C.0
D.3

A

Step-by-step explanation:

x^2+3=y

3x-y+1=0

3x+1=y

so x²+3=3x+1

x²-3x+2=0

x²-x-2x+2=0

x(x-1)-2(x-1)=0

(x-1)(x-2)=0

x=1,2

two solutions

hence, the required result is

step-by-step explanation:

suppose we have two matrices a and b

we will assume the two matrices

we have to compute b-a which means subtracting corresponding elements of a from b.

-

answer: i believe it is c

step-by-step explanation:

because 5+4=9 so it would be 3^9