If sec
o =
1/cos o
Cos, what is cos
o?

Given: sec0=1, secX=1/cosX

we hv to find cos0,

We Have given:

SecX = 1/cosX

multiply cosX both side to get

secX × cos X =cosX /cos X

i.e, secX × cosX = 1

Relace X by '0', coz we hv to find for this angle

so equation becomes

sec0 × cos 0 = 1

given sec 0 = 1

i.e, 1 × cos 0 = 1

i.e, cos 0 = 1

✌️:)

i need the table so i can see

step-by-step explanation:

step-by-step explanation:

∆abc has the points a(1, 7), b(-2, 2), and c(4, 2) as its vertices. formed with the point d(1, 2) as its third vertex, then ∆abd is triangle.