Find the perimeter of a rectangle with length 7x - 2 and width 5x^2 + 1.

10x^2 + 14x - 2

Step-by-step explanation:

So for the perimeter, you have to solve 2(7x-2) + 2(5x^2+1)

So distribute the 2s on both s we get 14x - 4 + 10x^2 + 2

This in standard form is 10x^2 + 14x - 2

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

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step-by-step explanation:

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