Se considera punctele A(-3,2) si B(5,12) varfuri ale triunghiului ABC. O dreapta care trece prin G, centrul de greutate al triunghiului ABC, si este paralela cu dreapta AC intersecteaza dreapta BC in E(10,2). Sa se afle coordonatele punctului C.

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

greater than one

step-by-step explanation:

27 +27 or 27times 2=54

the diffrence is 0