A curve has equation y=2x^2-3x
Find the set of values of x for which y>9

Good morning ☕️

Step-by-step explanation:

Here we have to solve this inequality 2x² - 3x - 9 > 0 for x.

In order to solve this inequality we need to factorize the expression at first:

2x² - 3x - 9 = 2x² - 3x - 3x + 3x - 9

                  = 2x² + 3x - (6x + 9)

                 = x(2x + 3) - 3(2x + 3)

                 = (2x + 3)(x - 3)

check the attached picture

conclusion:

the set of values of x for which y>9 is :

(-∞ , -3/2)∪(3 , +∞)

:)

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2

168

step-by-step explanation:

i am pretty sure that the answer is 168