2x+y=4
Y=x-5
Equations using substitution

x = 3

y = -2

Step-by-step explanation:

2x + y = 4; y = x - 5

First name the equation

2x + y = 4 ...(1)

y = x - 5. ...(2)

Now Substitute the value of y in equation (1)

2x + y = 4

2x + (x - 5) = 4

2x + x - 5 = 4

3x = 4 + 5

3x = 9

x = 9 ÷ 3

x = 3

Now, put the value of x = 3 in equation (2)

y = x - 5

y = 3 - 5

y = - 2

Thus, The Value of x is 3 and the value of y is -2

2x + y = 4

2(3) + (- 2) = 4

6 - 2 = 4

4 = 4

y = x - 5

- 2 = 3 - 5

- 2 = - 2

Hence, L.H.S = R.H.S

-TheUnknownScientist

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3