complete the sqaure to rewrite y=x^2-6x+16 in vertex form. then state whether the vertex is a maximum and give its coordinates!

y = (x-3) ^2 +7

Vertex (3,7)  minimum

Step-by-step explanation:

y=x^2-6x+16

The equation of a parabola in vertex form is

y = a(x - h)2 + k , where (h, k) is the vertex and a tells us where it opens up or down  a>0 opens up and a < 0 opens down

First complete the square

Take the coefficient of the x term, divide by 2 and square it

-6 /2 = -3  

(-3)^2 = 9

Take the 16 and split it into 9 and 7

y=x^2-6x+9 +7

y = (x-3) ^2 +7

The vertex is (3,7) and a=1

Since a =1, this opens up and if it opens up, the vertex is a minimum

(3,7) min

Step-by-step explanation:

y = x² - 6x + 16

Since coefficient of x² is 1, which is greater than 0.. it will have a minimum point.

y = x² - 2(x)(3) + 3² - 3² + 16

y = (x - 3)² - 9 + 16

y = (x - 3)² + 7

Vertex: (3,7)

step-by-step explanation: a reaction is first order. if the initial reactant concentration is 0.0200 m, and 25.0 days later the concentration is 6.25 x 10-4 m, then its half-life is:

the answer is thin because within context, the stanza concludes the and frail tone the people have toward each other, and the fact that it would be thin, makes the most sense compared to "pliable" or "not hard or firm to the touch". hope this , good luck.

step-by-step explanation:

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