A square has side length 6x+2. A rectangle with width 3x+1 has the same area as a square. What is the length of the rectangle

L = 12x + 4

Step-by-step explanation:

(see diagram for reference)

the area of the square

= (6x+2) (6x+2)  (factor out 2 from each parentheses)

= (2)(3x+1)(2)(3x+1)  (group like terms and simplify)

= 4(3x + 1)²

the area of the rectangle,

= (3x+1) (L)

It is given that the square and the circle have the same area, hence we equate the areas of square and rectangle:

4(3x + 1)² = (3x+1) (L)     (divide both sides by 3x+1)

4(3x + 1) = (L)   (rearranging and expanding the parentheses)

L = 12x + 4

Hope this helps

the solution is x=1

step-by-step explanation:

we are given our   equation as

let's assume

left side function is

right side function is

now, we can draw graph

and then we can get intersection point

the intersection point will be solution

so, the solution is

x=1