A dirt bike lanches off of a ramp that is 8 feet tall. The inital velocity of the dirt bike is 20 feet per second the hight is given by the equation h=16t^2+20t+8. What is the maximum hight the dirt bike reaches?

The correct answer is 8 feet.

Step-by-step explanation:

Height of the dirt bike is given by the equation h = 16 + 20 t +8.

Initial velocity of the dirt bike is 20 feet per second

Initial height of the dirt bike when it launches off the ramp is 8 feet.

To find the maximum h, we differentiate the function h with respect to t and equate the result to zero.

⇒ h = 0 = 32t + 20

and second order differentiation of h gives = 32.

This gives the value of the function maximum at t = -0.625 seconds.

This is absurd as the value of t cannot be negative.

Thus the dirt bike is going to fall off the ramp and is not going to gain any height, making the height at t = 0 the maximum height attained by it.

the answer is d

step-by-step explanation:

y+3=-4(x-2)

y+3=-4x+8

  -3         -3  

y=-4x+5