Solve for the zeros of the quadratic function f(x) = x + 5 – 2x2.
1. Put the quadratic function in standard form.
f(x) = –2x2 + x + 5
2. Set the function equal to 0 to create a quadratic equation.
–2x2 + x + 5 = 0
3. Determine the values for a, b, and c.
a =
b =
c =
4. Analyze the discriminant.
b2 – 4ac =
The quadratic function will have .

a= -2

b= 1

c= 5

b^2-4ac= 41

The quadratic function will have 2 real number zeros

Step-by-step explanation:

Edguinity

a= -2

b= 1

c= 5

b^2-4ac= 41

Step-by-step explanation:

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(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240