Please help!

If sin(xº)=cos(yº) find k if x=2k+3 and y=6k+7

answer

10

step-by-step explanation

the equation given is sin(x) = cos(y) with x = 2k + 3 and y = 6k + 7

substitute in 2k+ 3 for x in sin(x) and substitute in 6k + 7 for y in cos(y)

sin(x) = cos(y)

sin(2k + 3) = cos(6k + 7)

we know that sin(x) = cos(90 -x)

sin(2k + 3)

= cos(90 - (2k + 3) )

= cos(90 - 2k - 3)

= cos(87 - 2k)

substitute this into the equation sin(2k + 3) = cos(6k + 7)

sin(2k + 3) = cos(6k + 7)

cos(87 - 2k) = cos(6k + 7)

87 - 2k = 6k +7

80 = 8k

k = 10

answer: x=3 and y=4

step-by-step explanation:

something over 10 so ? /10

step-by-step explanation: