I need help on this plzzz

see below

Step-by-step explanation:

The exterior angle is equal to the sum of the opposite interior angles.

139 = <Q + <P

       = 6y+1 + 4y+8

       = 10y+9

139 = 10y+9

Subtract 9 from each side

130 = 10y

Divide each side by 10

13 = y

<P = 4y+8 = 4*13+8 = 60

<Q = 6y+1 = 6*13+1 =79

QPR =   We know this makes a straight line with 139

         = 180-139 = 41

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°