Will factored 7x^67x 6 7, x, start superscript, 6, end superscript as (3x^2)(4x^4)(3x 2 )(4x 4 )left parenthesis, 3, x, squared, right parenthesis, left parenthesis, 4, x, start superscript, 4, end superscript, right parenthesis. Olivia factored 7x^67x 6 7, x, start superscript, 6, end superscript as (7x^2)(x^3)(7x 2 )(x 3 )left parenthesis, 7, x, squared, right parenthesis, left parenthesis, x, cubed, right parenthesis. Which of them factored 7x^67x 6 7, x, start superscript, 6, end superscript correctly?

None of them factored correctly.

Step-by-step explanation:

We are to determine which of them factored correctly. We will do this by backward expansion of the factored terms.

For Will

For Olivia

We conclude therefore that none factored it correctly.

None of them factored 7x^6 correctly.

Question:

Will factored 7x^6 as (3x^2)(4x^4), Olivia factored 7x^6 as (7x^2)(x^3). Which of them factored 7x^6 correctly?

Step-by-step explanation:

Given;

Will factored 7x^6 as (3x^2)(4x^4)

To verify;

(3x^2)(4x^4) = 3 × 4 × x^2 × x^4 = 12 × x^(2+4) = 12x^6

(3x^2)(4x^4) = 12x^6

Wrong

Olivia factored 7x^6 as (7x^2)(x^3)

To verify;

(7x^2)(x^3) = 7 × x^2 × x^3 = 7 × x^(2+3) = 7x^5

(7x^2)(x^3) = 7x^5

Wrong

Both Will and Olivia are wrong. So,

None of them factored 7x^6 correctly.

answer:

your answer is: c. 196 7/8 in^3.