Let a and b be real numbers, where a b 0.
Which of the following functions could represent
the graph on the right?
o f(x)= x (x - a)(x - b)2
O f(x) = (x - a)(x - b)2
o f(x) = x(x - a)º(x - b)
o f(x) = x2(x - a) ?(x- b)2
DONE

Consider this equation. |y + 6| = 2 what can be concluded of the equation? check all that apply. there will be one solution. there will be two solutions. the solution to –(y + 6) = 2 will be also be a solution to the given absolute value equation. the solution(s) will be the number(s) on the number line 2 units away from –6. the value of y must be positive since the variable is inside absolute value signs.