A club began with 3 members. Each month, each member brought one new member. Which function can be used to determine the number of members x months after the club began? A. f(x) = 2x + 3 B. f(x) = 3x + 1 C. f(x) = 1.5(2)x D. f(x) = 3(2)x

In x th month, members =  . Option D.

Step-by-step explanation:

Given,

Initially number of members = 3

Every month each member brought 1 new member.

To find the number of members after x months.

Solution:

In 1st month, members = 3

In 2nd month, members = 3×3 = 9 = 3²

In 3rd month, members = 9×9 = 81 =

In 4th month, members = 81×81 = 81 = 6561 =

Hence,

In x th month, members =  

D

Step-by-step explanation:

The starting number is 3

And they bring in 1 member each month

That can be shown with the last equation

Good luck!

answerim :

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step-by-step explanation:

im not sure but my dad knows

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.